SSC CGL Ages Questions & Solutions

A sample of real SSC CGL Ages past-year questions, each with a worked solution and the correct answer highlighted. AthenaPrep has 120 Ages questions in all — sign up free to practise them timed.

Q1.SSC 2024
If the ratio of the ages of A and B is 3 : 4 and the sum of their ages is 28, then find the age of B.
- 18 years
- 16 years
- 14 years
- 17 years
Show solution
Let the ages of A and B be 3x and 4x respectively.
The sum of their ages is:
$3x + 4x = 28$
$7x = 28$
$x = 4$
Thus, age of B is:
$4x = 4 \times 4 = 16$
So, the correct option is B.

— worked solution by Athena AI
Q2.SSC 2021
Ratio of the present age of a motherto that of the daughteris 7 : 1. After 5 years the ratio will become 4 : 1. What is the difference (in years) in their present ages?
- 29
- 30
- 28
- 31
Show solution
Let the present age of the mother be 7x and the daughter be x. After 5 years, the ages will be 7x + 5 and x + 5. The ratio becomes:
$\frac{(7x + 5)}{(x + 5)} = \frac{4}{1}$
Cross-multiplying gives: $4(x + 5) = 7x + 5\Rightarrow 4x + 20 = 7x + 5$
Thus, $3x = 15 \Rightarrow x = 5$
The difference in their present ages is $7x - x = 6x = 30$
Thus, the answer is B. 30.

— worked solution by Athena AI
Q3.SSC 2021
The ratio of the present ages of A and B is 6:5. Four years ago, this ratio was 5:4. What will be the ratio of the ages of A and B after ten years?
- 11:15
- 17:15
- 15:11
- 15:17
Show solution
Let the present ages of A and B be 6x and 5x respectively.
Four years ago, their ages were 6x - 4 and 5x - 4:
(6x - 4) / (5x - 4) = 5 / 4.
Cross-multiplying gives:
4(6x - 4) = 5(5x - 4).
Solving gives x = 4.
Thus, present ages are 24 and 20. After 10 years, the ages will be 34 and 30, giving a ratio of 17:15.
Thus, the ratio after ten years is 17:15.

— worked solution by Athena AI
Q4.SSC 2021
If A is one third of B, B is twice of C, D is two-third of A and the average of A, B, C and D is 74, then the difference between A and C is:
- 32
- 26
- 28
- 24
Show solution
Let $A = 3k$, $B = 6k$, $C = 3k$, and $D = 2k$.
The average of $A$, $B$, $C$, and $D$ is:
$\frac{3k + 6k + 3k + 2k}{4} = 74$
Thus, $14k = 296 ightarrow k = 21.14$.
The difference between $A$ and $C$ is:
$A - C = 3k - k = 2k = 42$
Thus, the correct option is D.

— worked solution by Athena AI
Q5.SSC 2019
The ratio of ages of the father and mother was 11:10 when their son was born. The ratio of ages of the father and mother will be 19:18 when the son will be twice his present age. What is the ratio of present ages of father and mother?
- 15 : 14
- 14 : 13
- 16 : 15
- 17 : 16
Show solution
Ratio of parents present age is 11:10 And the ratio of ages of the father and mother will be 19:18 when the son will be twice his present age
Let the present age of son be x
Then the twice age will be 2x
According to question:
$\frac{11 + 2x}{10 + 2x} = \frac{19}{18}$
$18(11 + 2x) = 19(10 + 2x)$
$198 + 36x = 190 + 38x$
$8 = 2x$
$x = 4$
Ratio of present ages will be:
$\frac{11 + x}{10 + x} = \frac{11 + 4}{10 + 4}$

Required ratio is: (15/14).
A is correct choice.
Q6.SSC 2019
The present ages of A and are in the ratio 15 : 8. After 8 years their ages will be in the ratio 17 : 10. What will be the ratio of ages of A and B after 10 years from now?
- 10 : 7
- 8 : 5
- 5 : 3
- 7 : 4
Show solution
Let present age of A = $15x$ years and B = $8x$ years
According to ques,
=> $\frac{15x+8}{8x+8}=\frac{17}{10}$
=> $150x+80=136x+136$
=> $14x=136-80=56$
=> $x=\frac{56}{14}=4$
$\therefore$ Ratio of ages of A and B after 10 years from now = $\frac{15\times4+10}{8\times4+10}$
= $\frac{70}{42}=5:3$
=> Ans - (C)
Q7.SSC 2019
The sum of the current ages of Natasha and Krishna is 50 years. 10 years ago, Krishna was twice as old as Natasha. What is Krishna’s current age?
- 15 years
- 20 years
- 10 years
- 30 years
Show solution
Option D is correct,
Let us take the present age of Natasha is x and the present age of Krishna is y. So that,
x+y=50 ----- (i)
y=50-x
Ten year ago, Krishna was twice as old as Natasha so that,
(y-10)=2(x-10)
put the value of y
(50-x-10)=2x-20
from solving the equation we get
x=20
Put the value of x in equation (i)
20+y=50
y=30
So the present age of Krishna is 30 years.
Q8.SSC 2019
The sum of the present ages of a father and his son is 78 years. After five years, the ratio of their ages becomes 7 : 4. What is the present age (in years) of the father?
- 45
- 51
- 56
- 50
Show solution
Given,
Sum of present ages of father and son is 78 and their ratio after 5 years is 7:4
let the age of father and son after 5 years be 7x and 4x
sum of the present ages can be written as,
(7x-5) + (4x-5) = 78
7x + 4x - 10 = 78
11x - 10 = 78
11x = 88
x = 8
The age of father after 5 years is ${7}\times{8}$ = 56
therefore the present age of father is 56 - 5 = 51
Q9.SSC 2019
Five years ago, the ratio of the ages of A and B was 3 4. Five years from now,the ratio of their ages will be 4 : 5. What is the ratio of A and B, 10 years from now?
- 9:11
- 6:7
- 5:6
- 7:9
Show solution
Let the ages of A and B are 3p and 4p five years ago respectively
   A    B
5 years ago 3p    4p
After 5 years 3p+10 4p+10
After 10 years 3p+15 4p+15
Given ratio of ages of A and B after 5 years is 4:5
$=$ > $\ \frac{\ 3p+10}{4p+10}=\ \frac{\ 4}{5}$
$\ \ 15p+50=\ 16p+40$
$p=10$
Therefore ratio of ages of A and B after 10 years = 3p+15: 4p+15
= 3(10)+15 : 4(10)+15
    = 45:55
    = 9:11
Q10.SSC 2018
Present ages of A and B are in ratio 3 : 5. 7 years later B's age will be twice the age of C. If C celebrated his 10 th birthday 4 years ago, then what is the present age (in years) of A?
- 14
- 21
- 28
- 42
Show solution
C celebrated his 10th birthday 4 years ago, => C's present age = $10+4=14$ years
Also, B's age after 7 years = $2\times(14+7)=2\times21=42$ years
=> B's present age = $42-7=35$ years
$\therefore$ A's present age = $\frac{3}{5}\times35=3\times7=21$ years
=> Ans - (B)
Q11.SSC 2017
The ratio of present ages of L and N is 7 : 5. If the age of N after seven years will be 32 years, then what is the present age (in years) of L?
- 49
- 35
- 28
- 42
Show solution
Let present ages of L and N be $7x$ years and $5x$ years respectively.
Thus, N's age after 7 years = $5x+7=32$
=> $5x=32-7=25$
=> $x=\frac{25}{5}=5$
$\therefore$ L's age = $7\times5=35$ years
=> Ans - (B)
Q12.SSC 2013
The average age of father and his son is 22 years. The ratio of their ages is 10 : 1 respectively. What is the age of the son ?
- 24
- 4
- 40
- 14
Show solution
Let son's age = $x$ years
=> Father's age = $10x$ years
Average age = $\frac{x+10x}{2}=22$
=> $11x=22\times2=44$
=> $x=\frac{44}{11}=4$ years
=> Ans - (B)

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SSC CGL Ages Questions & Solutions

Q1.SSC 2024

If the ratio of the ages of A and B is 3 : 4 and the sum of their ages is 28, then find the age of B.

18 years
16 years
14 years
17 years

Show solution

Let the ages of A and B be 3x and 4x respectively.

The sum of their ages is:

$3x + 4x = 28$

$7x = 28$

$x = 4$

Thus, age of B is:

$4x = 4 \times 4 = 16$

So, the correct option is B.

— worked solution by Athena AI

Q2.SSC 2021

Ratio of the present age of a motherto that of the daughteris 7 : 1. After 5 years the ratio will become 4 : 1. What is the difference (in years) in their present ages?

Show solution

Let the present age of the mother be 7x and the daughter be x. After 5 years, the ages will be 7x + 5 and x + 5. The ratio becomes:

$\frac{(7x + 5)}{(x + 5)} = \frac{4}{1}$

Cross-multiplying gives: $4(x + 5) = 7x + 5\Rightarrow 4x + 20 = 7x + 5$

Thus, $3x = 15 \Rightarrow x = 5$

The difference in their present ages is $7x - x = 6x = 30$

Thus, the answer is B. 30.

— worked solution by Athena AI

Q3.SSC 2021

The ratio of the present ages of A and B is 6:5. Four years ago, this ratio was 5:4. What will be the ratio of the ages of A and B after ten years?

11:15
17:15
15:11
15:17

Show solution

Let the present ages of A and B be 6x and 5x respectively.

Four years ago, their ages were 6x - 4 and 5x - 4:

(6x - 4) / (5x - 4) = 5 / 4.

Cross-multiplying gives:

4(6x - 4) = 5(5x - 4).

Solving gives x = 4.

Thus, present ages are 24 and 20. After 10 years, the ages will be 34 and 30, giving a ratio of 17:15.

Thus, the ratio after ten years is 17:15.

— worked solution by Athena AI

Q4.SSC 2021

If A is one third of B, B is twice of C, D is two-third of A and the average of A, B, C and D is 74, then the difference between A and C is:

Show solution

Let $A = 3k$, $B = 6k$, $C = 3k$, and $D = 2k$.

The average of $A$, $B$, $C$, and $D$ is:

$\frac{3k + 6k + 3k + 2k}{4} = 74$

Thus, $14k = 296 ightarrow k = 21.14$.

The difference between $A$ and $C$ is:

$A - C = 3k - k = 2k = 42$

Thus, the correct option is D.

— worked solution by Athena AI

Q5.SSC 2019

The ratio of ages of the father and mother was 11:10 when their son was born. The ratio of ages of the father and mother will be 19:18 when the son will be twice his present age. What is the ratio of present ages of father and mother?

15 : 14
14 : 13
16 : 15
17 : 16

Show solution

Ratio of parents present age is 11:10 And the ratio of ages of the father and mother will be 19:18 when the son will be twice his present age

Let the present age of son be x

Then the twice age will be 2x

According to question:

$\frac{11 + 2x}{10 + 2x} = \frac{19}{18}$

$18(11 + 2x) = 19(10 + 2x)$

$198 + 36x = 190 + 38x$

$8 = 2x$

$x = 4$

Ratio of present ages will be:

$\frac{11 + x}{10 + x} = \frac{11 + 4}{10 + 4}$

Required ratio is: (15/14).

A is correct choice.

Q6.SSC 2019

The present ages of A and are in the ratio 15 : 8. After 8 years their ages will be in the ratio 17 : 10. What will be the ratio of ages of A and B after 10 years from now?

10 : 7
8 : 5
5 : 3
7 : 4

Show solution

Let present age of A = $15x$ years and B = $8x$ years

According to ques,

=> $\frac{15x+8}{8x+8}=\frac{17}{10}$

=> $150x+80=136x+136$

=> $14x=136-80=56$

=> $x=\frac{56}{14}=4$

$\therefore$ Ratio of ages of A and B after 10 years from now = $\frac{15\times4+10}{8\times4+10}$

= $\frac{70}{42}=5:3$

=> Ans - (C)

Q7.SSC 2019

The sum of the current ages of Natasha and Krishna is 50 years. 10 years ago, Krishna was twice as old as Natasha. What is Krishna’s current age?

15 years
20 years
10 years
30 years

Show solution

Option D is correct,

Let us take the present age of Natasha is x and the present age of Krishna is y. So that,

x+y=50 ----- (i)

y=50-x

Ten year ago, Krishna was twice as old as Natasha so that,

(y-10)=2(x-10)

put the value of y

(50-x-10)=2x-20

from solving the equation we get

x=20

Put the value of x in equation (i)

20+y=50

y=30

So the present age of Krishna is 30 years.

Q8.SSC 2019

The sum of the present ages of a father and his son is 78 years. After five years, the ratio of their ages becomes 7 : 4. What is the present age (in years) of the father?

Show solution

Given,

Sum of present ages of father and son is 78 and their ratio after 5 years is 7:4

let the age of father and son after 5 years be 7x and 4x

sum of the present ages can be written as,

(7x-5) + (4x-5) = 78

7x + 4x - 10 = 78

11x - 10 = 78

11x = 88

x = 8

The age of father after 5 years is ${7}\times{8}$ = 56

therefore the present age of father is 56 - 5 = 51

Q9.SSC 2019

Five years ago, the ratio of the ages of A and B was 3 4. Five years from now,the ratio of their ages will be 4 : 5. What is the ratio of A and B, 10 years from now?

9:11
6:7
5:6
7:9

Show solution

Let the ages of A and B are 3p and 4p five years ago respectively

A B

5 years ago 3p 4p

After 5 years 3p+10 4p+10

After 10 years 3p+15 4p+15

Given ratio of ages of A and B after 5 years is 4:5

$=$ > $\ \frac{\ 3p+10}{4p+10}=\ \frac{\ 4}{5}$

$\ \ 15p+50=\ 16p+40$

$p=10$

Therefore ratio of ages of A and B after 10 years = 3p+15: 4p+15

= 3(10)+15 : 4(10)+15

= 45:55

= 9:11

Q10.SSC 2018

Present ages of A and B are in ratio 3 : 5. 7 years later B's age will be twice the age of C. If C celebrated his 10 th birthday 4 years ago, then what is the present age (in years) of A?

Show solution

C celebrated his 10th birthday 4 years ago, => C's present age = $10+4=14$ years

Also, B's age after 7 years = $2\times(14+7)=2\times21=42$ years

=> B's present age = $42-7=35$ years

$\therefore$ A's present age = $\frac{3}{5}\times35=3\times7=21$ years

=> Ans - (B)

Q11.SSC 2017

The ratio of present ages of L and N is 7 : 5. If the age of N after seven years will be 32 years, then what is the present age (in years) of L?

Show solution

Let present ages of L and N be $7x$ years and $5x$ years respectively.

Thus, N's age after 7 years = $5x+7=32$

=> $5x=32-7=25$

=> $x=\frac{25}{5}=5$

$\therefore$ L's age = $7\times5=35$ years

=> Ans - (B)

Q12.SSC 2013

The average age of father and his son is 22 years. The ratio of their ages is 10 : 1 respectively. What is the age of the son ?

Show solution

Let son's age = $x$ years

=> Father's age = $10x$ years

Average age = $\frac{x+10x}{2}=22$

=> $11x=22\times2=44$

=> $x=\frac{44}{11}=4$ years

=> Ans - (B)

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