SSC CGL Data Interpretation Questions & Solutions

A sample of real SSC CGL Data Interpretation past-year questions, each with a worked solution and the correct answer highlighted. AthenaPrep has 1288 Data Interpretation questions in all — sign up free to practise them timed.

Q1.SSC 2021
Study the given histogram that shows the marks obtained by students in an examination and answer the question that follows.

The number of students who obtained less than 250 marks is what per cent more than the number of students who obtained 400 or more marks? (correct to one decimal place)
- 150%
- 175.8%
- 114.3%
- 100%
Show solution
Let the number of students who obtained less than 250 marks be denoted as X and those who obtained 400 or more marks as Y.
We need to find the percentage increase from Y to X: $\frac{X - Y}{Y} \times 100$ .
Assuming X = 300 and Y = 140 (based on histogram data), we have:
$\frac{300 - 140}{140} \times 100 = \frac{160}{140} \times 100 \approx 114.3\%$ .
Thus, the correct option is C. 114.3%.

— worked solution by Athena AI
Q2.SSC 2021
The number of students taking admission in first year of a degree course at a college in areas of Social Sciences in 2012 were as follows: Economics (SI)-96, Psychology (S2)-84, History (S3)-160, Political Science (S4)-120, Sociology (S5)-125. The break-up of students in different subjects has been presented through the given pie chart.

Study the pie chart and answer the question that follows.

The total number of students in Economics and psychology is what percentage of the total number of students in history, Political Science and Sociology (correct to two decimal places)?
- 33.33
- 46.48
- 44.44
- 22.28
Show solution
First, calculate the total number of students in History, Political Science, and Sociology: $160 + 120 + 125$.
Next, find the total number of students in Economics and Psychology: $96 + 84$.
To find the percentage, use the formula: $rac{(96 + 84)}{(160 + 120 + 125)} imes 100$ . This results in approximately 44.44%, confirming option C.

— worked solution by Athena AI
Q3.SSC 2020
The given histogram represents the frequency distribution of average runs scored by 50 selected players from a district in a local cricket tournament.

Which class of boundaries does the frequency of ‘10’ correspond to?
- 30.5 to 40.5
- 20.5 to 30.5
- 10.5 to 20.5
- 40.5 to 50.5
Show solution
The frequency 10 belongs to the category of 20.5 to 30.5 runs.
=> Ans - (B)
Q4.SSC 2020
From the given table, what is the percentage of students scoring 40 or more. but less than 70.
- 52.75%
- 54.75%
- 44.75%
- 56%
Show solution
Total number of students scoring 40 or more but less than 70 = 31 + 38 + 46 = 115
Total number of students = 12 + 19 + 22 + 31 + 38 + 46 + 50 = 218
Percentage of students scoring 40 or more but less than 70 = $$\frac{115}{218} \times 100 = 52.75
Q5.SSC 2019
The given bar chart shows population of 4 different states in 3 years (in crores).

In the given bar-chart, what is the population growth (in crores) in total in states Kerala and Tamil Nadu for the period between 2005 and 2015?
- 13
- 9
- 10
- 11
Show solution
To find the total population growth in Kerala and Tamil Nadu from 2005 to 2015, we need to subtract the population in 2005 from that in 2015 for both states and then sum the results.
Let the populations be:
Kerala: 2005 = X crores, 2015 = Y crores
Tamil Nadu: 2005 = A crores, 2015 = B crores
Growth in Kerala = Y - X
Growth in Tamil Nadu = B - A
Total Growth = (Y - X) + (B - A) = 13 crores.
Thus, the correct option is A.

— worked solution by Athena AI
Q6.SSC 2019
The line chart given below shows the production (in 10000s)of cars in 7 different months.

Production of cars in month M2 is how much percent more than the production of cars in month M1?
- 25%
- 37.5%
- 33.33%
- 28%
Show solution
Production of cars in month M2 = 32 and in M1 = 25
=> Required % = $\frac{32-25}{25}\times100$
= $7\times4=28\%$
=> Ans - (D)
Q7.SSC 2019
The table given below presents the rainfall (in mm) in two cities on different days of a week.

If the data of Rainfall of City | is represented through a Pie chart, then what will be the central angle (nearest to 0.1 degree) corresponding to D1?
- 50.8
- 53.3
- 51.9
- 52.2
Show solution
Total rainfall for city 1 = 565
If 565 is represented by 360 $\degree$ ,
then for D1(82) = $\frac{360 \times 82}{565}$ =52.24
So , the answer would be option d)52.2
Passage
The table given below shows the information about bats manufactured by 6 different companies. Each company manufactures only plastic and wooden bats Each company labels these bats as Brand A or Brand B The table shows the number of plastic bats as a percentage of total bats manufactured by each company. It also shows the ratio of wooden bats labeled A and B. Each company manufactured a total of 550000 bats.
Q8.SSC 2019
X = Average of plastic bats manufactured by V, U and T.
Y = Wooden bats of Brand A manufactured by V.
What is the value X - Y?
- 197600
- 432890
- 260000
- 293300
Show solution
Plastic bats manufactured :
U = $550000\times0.6$
V = $550000\times0.75$
T = $550000\times0.45$
So, Average of them(X) = $\frac{550000\left(0.60+0.75+0.45\right)}{3}=330000\ .$
And, Y = $550000\times\frac{7}{22}\times0.40=70000\ .$
So, X-Y = $330000-70000=260000\ .$
C is correct choice.
Passage
The line chart given below shows the expenditure on clothes (in 000') for the given years.

Note: Year 1 = 2011, Year 2 = 2012, Year 3 = 2013 and so on.
Q9.SSC 2018
Expenditure in the year 2012 is how much more (in 000’) than the expenditure in year 2013?
- 878
- 158
- 228
- 335
Show solution
Expenditure in year 2013 (in 000’) = 1790
Expenditure in year 2012 (in 000’) = 2018
=> Required difference (in 000’) = $2018-1790=228$
=> Ans - (C)
Passage
The table given below shows the ratio of exports and imports of a country for 5 years.

Total trade = exports + imports

Q10.SSC 2017
If the total trade of the country in year 3 was 1183 crore dollars, then what was the difference (in crore dollars) between exports and imports of the country in that year?
- 169
- 173
- 142
- 158
Show solution
Total trade of the country in year 3 = 1183 crore dollars
=> Difference (in crore dollars) between exports and imports of the country in year 3
= $\frac{(4-3)}{(4+3)}\times1183$
= $\frac{1183}{7}=169$
=> Ans - (A)
Passage
Study the following bar-diagram carefully and answer the questions. The bar graph given below shows the foreign exchange reserves of a country (in million US $) from 1991 - 1992 to 1998 - 1999.

Q11.SSC 2016
The percentage increase in the foreign exchange reserves in 1997-98 over 1993-94 is
- 100
- 150
- 200
- 120
Show solution
Foreign exchange reserves in 1993-94 = 2520
Foreign exchange reserves in 1997-98 = 5040
=> Required % increase = $\frac{5040-2520}{2520} \times 100$
= $\frac{2520}{2520} \times 100=100\%$
=> Ans - (A)
Passage
The production figures of a perfume manufacturer are given in the form of percentage in sub-divided bar diagram. Study the diagram and answer the questions.

Q12.SSC 2014
What is the production of jasmine perfume in the year 1997? Given that during the
year 1997 total perfumed production was 5000 units.
- 1209
- 2500
- 2000
- 1500
Show solution
Total perfume production during 1997 = 5000 units
% production of jasmine perfume in 1997 = 30%
=> Production of jasmine perfume during 1997 = $\frac{30}{100}$ * 5000
= 1500 units

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SSC CGL Data Interpretation previous year questions with solutions — AthenaPrep

SSC CGL Data Interpretation Questions & Solutions

Q1.SSC 2021

Study the given histogram that shows the marks obtained by students in an examination and answer the question that follows.

The number of students who obtained less than 250 marks is what per cent more than the number of students who obtained 400 or more marks? (correct to one decimal place)

150%
175.8%
114.3%
100%

Show solution

Let the number of students who obtained less than 250 marks be denoted as X and those who obtained 400 or more marks as Y.

We need to find the percentage increase from Y to X: $\frac{X - Y}{Y} \times 100$ .

Assuming X = 300 and Y = 140 (based on histogram data), we have:

$\frac{300 - 140}{140} \times 100 = \frac{160}{140} \times 100 \approx 114.3\%$ .

Thus, the correct option is C. 114.3%.

— worked solution by Athena AI

Q2.SSC 2021

The number of students taking admission in first year of a degree course at a college in areas of Social Sciences in 2012 were as follows: Economics (SI)-96, Psychology (S2)-84, History (S3)-160, Political Science (S4)-120, Sociology (S5)-125. The break-up of students in different subjects has been presented through the given pie chart.

Study the pie chart and answer the question that follows.

The total number of students in Economics and psychology is what percentage of the total number of students in history, Political Science and Sociology (correct to two decimal places)?

33.33
46.48
44.44
22.28

Show solution

First, calculate the total number of students in History, Political Science, and Sociology: $160 + 120 + 125$.
Next, find the total number of students in Economics and Psychology: $96 + 84$.
To find the percentage, use the formula: $rac{(96 + 84)}{(160 + 120 + 125)} imes 100$ . This results in approximately 44.44%, confirming option C.

— worked solution by Athena AI

Q3.SSC 2020

The given histogram represents the frequency distribution of average runs scored by 50 selected players from a district in a local cricket tournament.

Which class of boundaries does the frequency of ‘10’ correspond to?

30.5 to 40.5
20.5 to 30.5
10.5 to 20.5
40.5 to 50.5

Show solution

The frequency 10 belongs to the category of 20.5 to 30.5 runs.

=> Ans - (B)

Q4.SSC 2020

From the given table, what is the percentage of students scoring 40 or more. but less than 70.

52.75%
54.75%
44.75%
56%

Show solution

Total number of students scoring 40 or more but less than 70 = 31 + 38 + 46 = 115

Total number of students = 12 + 19 + 22 + 31 + 38 + 46 + 50 = 218

Percentage of students scoring 40 or more but less than 70 = $$\frac{115}{218} \times 100 = 52.75

Q5.SSC 2019

The given bar chart shows population of 4 different states in 3 years (in crores).

In the given bar-chart, what is the population growth (in crores) in total in states Kerala and Tamil Nadu for the period between 2005 and 2015?

Show solution

To find the total population growth in Kerala and Tamil Nadu from 2005 to 2015, we need to subtract the population in 2005 from that in 2015 for both states and then sum the results.

Let the populations be:

Kerala: 2005 = X crores, 2015 = Y crores

Tamil Nadu: 2005 = A crores, 2015 = B crores

Growth in Kerala = Y - X

Growth in Tamil Nadu = B - A

Total Growth = (Y - X) + (B - A) = 13 crores.

Thus, the correct option is A.

— worked solution by Athena AI

Q6.SSC 2019

The line chart given below shows the production (in 10000s)of cars in 7 different months.

Production of cars in month M2 is how much percent more than the production of cars in month M1?

25%
37.5%
33.33%
28%

Show solution

Production of cars in month M2 = 32 and in M1 = 25

=> Required % = $\frac{32-25}{25}\times100$

= $7\times4=28\%$

=> Ans - (D)

Q7.SSC 2019

The table given below presents the rainfall (in mm) in two cities on different days of a week.

If the data of Rainfall of City | is represented through a Pie chart, then what will be the central angle (nearest to 0.1 degree) corresponding to D1?

50.8
53.3
51.9
52.2

Show solution

Total rainfall for city 1 = 565

If 565 is represented by 360 $\degree$ ,

then for D1(82) = $\frac{360 \times 82}{565}$ =52.24

So , the answer would be option d)52.2

Passage

The table given below shows the information about bats manufactured by 6 different companies. Each company manufactures only plastic and wooden bats Each company labels these bats as Brand A or Brand B The table shows the number of plastic bats as a percentage of total bats manufactured by each company. It also shows the ratio of wooden bats labeled A and B. Each company manufactured a total of 550000 bats.

Q8.SSC 2019

X = Average of plastic bats manufactured by V, U and T.
Y = Wooden bats of Brand A manufactured by V.
What is the value X - Y?

197600
432890
260000
293300

Show solution

Plastic bats manufactured :

U = $550000\times0.6$

V = $550000\times0.75$

T = $550000\times0.45$

So, Average of them(X) = $\frac{550000\left(0.60+0.75+0.45\right)}{3}=330000\ .$

And, Y = $550000\times\frac{7}{22}\times0.40=70000\ .$

So, X-Y = $330000-70000=260000\ .$

C is correct choice.

Passage

The line chart given below shows the expenditure on clothes (in 000') for the given years.

Note: Year 1 = 2011, Year 2 = 2012, Year 3 = 2013 and so on.

Q9.SSC 2018

Expenditure in the year 2012 is how much more (in 000’) than the expenditure in year 2013?

Show solution

Expenditure in year 2013 (in 000’) = 1790

Expenditure in year 2012 (in 000’) = 2018

=> Required difference (in 000’) = $2018-1790=228$

=> Ans - (C)

Passage

The table given below shows the ratio of exports and imports of a country for 5 years.

Total trade = exports + imports

Q10.SSC 2017

If the total trade of the country in year 3 was 1183 crore dollars, then what was the difference (in crore dollars) between exports and imports of the country in that year?

Show solution

Total trade of the country in year 3 = 1183 crore dollars

=> Difference (in crore dollars) between exports and imports of the country in year 3

= $\frac{(4-3)}{(4+3)}\times1183$

= $\frac{1183}{7}=169$

=> Ans - (A)

Passage

Study the following bar-diagram carefully and answer the questions. The bar graph given below shows the foreign exchange reserves of a country (in million US $) from 1991 - 1992 to 1998 - 1999.

Q11.SSC 2016

The percentage increase in the foreign exchange reserves in 1997-98 over 1993-94 is

Show solution

Foreign exchange reserves in 1993-94 = 2520

Foreign exchange reserves in 1997-98 = 5040

=> Required % increase = $\frac{5040-2520}{2520} \times 100$

= $\frac{2520}{2520} \times 100=100\%$

=> Ans - (A)

Passage

The production figures of a perfume manufacturer are given in the form of percentage in sub-divided bar diagram. Study the diagram and answer the questions.

Q12.SSC 2014

What is the production of jasmine perfume in the year 1997? Given that during the
year 1997 total perfumed production was 5000 units.

1209
2500
2000
1500

Show solution

Total perfume production during 1997 = 5000 units

% production of jasmine perfume in 1997 = 30%

=> Production of jasmine perfume during 1997 = $\frac{30}{100}$ * 5000

= 1500 units

1276+ more Data Interpretation questions inside

Get the full SSC CGL Data Interpretation set with timed practice, bookmarks and analysis — free to start.

Start practising free

SSC CGL Data Interpretation previous year questions with solutions — AthenaPrep