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PYQsSSC CGL General Intelligence & ReasoningDirections

SSC CGL Directions Questions & Solutions

A sample of real SSC CGL Directions past-year questions, each with a worked solution and the correct answer highlighted. AthenaPrep has 266 Directions questions in all — sign up free to practise them timed.

  1. Q1.SSC 2023

    Salman starts from his office and drives 29 km towards South. Then he turns right and drives 16 km, again he turns right and drives 29 km. Finally he turns right and drives 13 km. At what distance is he from his start point in a straight line?

    • 29 km

    • 3 km

    • 16 km

    • 13 km

    Show solution

    Salman drives 29 km South, then 16 km East, then 29 km North, and finally 13 km West. His final position is 3 km South of the starting point. Thus, the straight-line distance from the start point is 3 km.

    — worked solution by Athena AI

  2. Q2.SSC 2023

    Indira starts from point A, which is 7 km towards East of point B. From point A, she drives 4 km towards East. From here, she takes a left turn and drives 9 km. She then takes a left turn, drives 9 km and stops at point C. If from point C, Indira drives 9 km towards South, how far will she be from point B?

    • 2 km

    • 4 km

    • 1 km

    • 3 km

    Show solution

    Indira starts 7 km east of B, drives 4 km east, then 9 km south, and finally 9 km west to point C. From C, driving 9 km south places her 2 km away from point B.

    — worked solution by Athena AI

  3. Q3.SSC 2020

    Hospital is 12 km towards east of Rupin’s house. His school is 5 km towards south of Hospital. What is the shortest distance between Rupin’s house and school?

    • 16 km

    • 17 km

    • 12 km

    • 13 km

    Show solution

    From the Pythagoras,

    (AC)2=(AB)2+ (<strong></strong>BC)2(AC)^2 = (AB)^2 + (<strong></strong>BC)^2(AC)2=(AB)2+ (<strong></strong>BC)2

    (AC)2=(12)2+(5)2(AC)^2 = (12)^2 + (5)^2(AC)2=(12)2+(5)2

    (AC)2=169(AC)^2 = 169(AC)2=169

    AC = 13 km

    Shortest distance = 13 km.

  4. Q4.SSC 2019

    In a morning after sunrise, a boy rode his bicycle 4 km towards West. Then he took right turn and rode 6 km then he took right turn and rode 6 km to reach his school. In which direction the School is form the starling point?

    • North-West

    • North-East

    • South-East

    • South-West

    Show solution

    The boy rides 4 km West, turns right (North), rides 6 km, then turns right (East) and rides 6 km to school. The school is 6 km North of the starting point. Thus, the school is in the North-East direction from the starting point. The correct answer is B.

    — worked solution by Athena AI

  5. Q5.SSC 2019

    Rama walks from his university campus 4 km towards north and then turns to the right to reach his department. Alter walking 2.5 km from the department he turns to the left and walks 4 km and reached Conference hall. Now in which direction is he from the starting place?

    • South-West

    • North-East

    • South

    • West

    Show solution

    Rama walks from his university campus 4 km towards north and then turns to the right to reach his department. Alter walking 2.5 km from the department he turns to the left and walks 4 km and reached Conference hall.

    So he is in the north east direction from the starting place. (The dashed line shows the direction)

    Option B is correct.

  6. Q6.SSC 2018

    A, B, C and D are playing a game of carrom. A, C and B, D are partners. C is to the left of D who is facing South. Then A is facing

    • North

    • South

    • East

    • West

    Show solution

    As per the given question, final arrangement will be-

    A is facing towards East in the above arrangement.

    Hence, option C is the correct answer.

  7. Q7.SSC 2018

    A hawker starts from his home. He pushes his cart 2 km North, then he turns West and walks 3 km, then he turns South and walks 7 km, then he turns to his left and walks 3 km. Where is he with respect to his home?

    • 5 km North

    • 5 km South

    • 9 km South

    • 9 km North

    Show solution

    The hawker walks 2 km North to point A, turns West and walks 3 km to point B, turns South and walks 7 km to point C, and finally turns left (East) and walks 3 km to point D. The final position is 5 km South of his starting position.

    Thus, he is 5 km South from his home.

    — worked solution by Athena AI

  8. Q8.SSC 2017

    A and B start from the same point. A cycles 8 km South, then turns to her right and cycles 5 km. B cycles 3 km North, then turns West and cycles 5 km, then turns to her left and cycles 4 km. Where is B with respect to A now?

    • 7 km North

    • 7 km South

    • 15 km North

    • 15 km South

    Show solution

    Let both A and B start from point S. A's path is shown by black and B's by blue.

    A cycles 8 km south and reaches T, then takes right turn and reaches point U by cycling 5 km.

    Similarly, B cycles north for 3 km and reaches R, then turns left for 5 km and finally stops at point P.

    Thus, PU = 8 + 3 - 4 = 7 km

    ∴\therefore∴ B is 7 km to the north of A.

    => Ans - (A)

  9. Q9.SSC 2017

    A man walks 7 km North, then turns West and walks 3 km, then turns South and walks 7 km, then turns to his right and walks 5 kms. Where is he now with reference to his starting position?

    • 2 km to the West of the starting point.

    • 8 km to the East of the starting point.

    • 8 km to the West of the starting point.

    • 2 km to the East of the starting point

    Show solution

    Distance between E to A = 5 + 3 = 8 km

    ∴\therefore∴ Man is 8 km to the west of the starting point.

  10. Q10.SSC 2016

    A man walks 5 kilometre towards South and then turns to the right. After walking 3 kilometre, he turns to the left and walks 5 kilometre. Now in which direction is he from the starting point?

    • West

    • South

    • North-East

    • South-West

    Show solution

    Let the man started from point A and walked 5 km towards south and reached point B, then he turned right and walked west and reached C. Finally, he turned left and walked towards south for 5 km and stopped at point D.

    Thus, he is in south-west direction from starting point.

    => Ans - (D)

  11. Q11.SSC 2014

    ‘A’ walks 10 metres in front and 10 metres to the right. And after walking staright takes a right turn and walks 5 metres. How far is he now from his starting point?

    • 5√5\surd5√5 meter

    • 10 √5\surd5√5 meter

    • 5 meter

    • 5 √10\surd10√10 meter

    Show solution

    Using Pythagoras : Shortest Distance = √(52+102)\surd(5^2 + 10^2)√(52+102) = 5 √(5)\surd(5)√(5)

  12. Q12.SSC 2013

    Rohan walks a distance of 3 km towards North, then turns to his left and walks for2 km. He again turns left and walks for 3 km. At this point he turns to his left and walks for 3 km. How many kilometres is he from the starting point ?

    • 1 km

    • 2 krn

    • 3 km

    • 4 km

    Show solution

    Rohan's positions wrt to starting point are as follows
    3 km towards North
    turns to his left and walks for2 km:13<spanclass="redactor−invisible−space">\sqrt{13}<span class="redactor-invisible-space">13​<spanclass="redactor−invisible−space"> towrads NW
    turns left and walks for 3 km: 2 km west
    turns to his left and walks for 3 km.: 1 km EAST.

    hence the correct answer is option A



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SSC CGL Directions previous year questions with solutions — AthenaPrep